Nursing Elites

1. In a patient with asthma, which of the following is the most important indicator of respiratory function?

• A. Oxygen saturation.
• B. Respiratory rate.
• C. Arterial blood gases.
• D. Peak expiratory flow rate.

Correct answer: D

Rationale: The peak expiratory flow rate is the most important indicator of respiratory function in asthma because it measures how quickly air can be exhaled, reflecting the severity of airflow limitation. Oxygen saturation (Choice A) is important in assessing oxygenation, but it does not directly reflect respiratory function. Respiratory rate (Choice B) can provide information on breathing patterns but does not quantify airflow limitation. Arterial blood gases (Choice C) give information about gas exchange but are not as specific for assessing asthma control and severity as peak expiratory flow rate.

2. A client is returning home after arthroscopy of the shoulder. The nurse should tell the client:

• A. To resume full activity the next day
• B. Not to eat or drink anything until the next morning
• C. To keep the shoulder completely immobilized for the rest of the day
• D. To report to the physician the development of fever or redness and heat at the site

Correct answer: D

Rationale: After arthroscopy, it is important for the client to report any signs of infection, such as the development of fever or redness and heat at the site, to the physician promptly. Options A, B, and C are incorrect. The client should not resume full activity the next day as rest and limited movement are usually recommended post-arthroscopy. It is not necessary to withhold food or fluids until the next morning; the client may resume the usual diet immediately unless otherwise instructed. While immobilization may be recommended for a period, keeping the shoulder completely immobilized for the rest of the day is not typically necessary post-arthroscopy.

3. Blood for arterial blood gas determinations is drawn from a client with pneumonia, and testing reveals a pH of 7.45, PCO2 of 30 mm Hg, and HCO3 of 19 mEq/L. The nurse interprets these results as indicative of:

• A. Compensated metabolic acidosis
• B. Compensated respiratory alkalosis
• C. Uncompensated metabolic alkalosis
• D. Uncompensated respiratory acidosis

Correct answer: B

Rationale: The correct answer is 'Compensated respiratory alkalosis.' In this case, the client's pH is within the normal range (7.35-7.45), indicating compensation. The low PCO2 (30 mm Hg) suggests respiratory alkalosis, while the low HCO3 (19 mEq/L) is also consistent with a compensatory response. Therefore, the client has a primary respiratory alkalosis that is being compensated for by metabolic acidosis. Choices A, C, and D are incorrect because they do not fit the pattern of the given blood gas values, which indicate respiratory alkalosis with metabolic compensation.

4. Which information about mammograms is most important to provide a post-menopausal female client?

• A. Breast self-examinations are not necessary if annual mammograms are obtained.
• B. Radiation exposure is minimized by shielding the abdomen with a lead-lined apron.
• C. Yearly mammograms should be done regardless of previous normal screenings.
• D. Women at high risk should have annual routine and ultrasound mammograms.

Correct answer: C

Rationale: The most important information to provide a post-menopausal female client regarding mammograms is that yearly mammograms should be done regardless of previous normal screenings. It is crucial for post-menopausal women to continue regular mammograms as they are at a higher risk for breast cancer. Option A is incorrect as breast self-examinations are still recommended in addition to mammograms. Option B is not the most important information compared to the importance of regular mammograms. Option D is not the most important advice for all post-menopausal females but specifically for those at high risk, indicating a more targeted approach.

5. What is the most common cause of urinary tract infections (UTIs)?

• A. Escherichia coli infection
• B. Staphylococcus aureus infection
• C. Pseudomonas aeruginosa infection
• D. Klebsiella pneumoniae infection

Correct answer: A

Rationale: Escherichia coli is the most common cause of urinary tract infections (UTIs). It is responsible for the majority of UTIs, especially in women. E. coli is a normal inhabitant of the bowel and can enter the urinary tract through the urethra, leading to infection. Staphylococcus aureus, Pseudomonas aeruginosa, and Klebsiella pneumoniae are less common causes of UTIs compared to E. coli. Staphylococcus aureus typically causes skin and soft tissue infections, Pseudomonas aeruginosa is more commonly associated with healthcare-associated infections, and Klebsiella pneumoniae is known for causing pneumonia and other respiratory infections.

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