HESI RN
HESI Medical Surgical Exam
1. A client with Diabetes Insipidus (DI) is being cared for by a nurse. Which data warrants the most immediate intervention by the nurse?
- A. Serum sodium of 185 mEq/L (185 mmol/L)
- B. Dry skin with poor skin turgor
- C. Apical rate of 110 beats per minute
- D. Polyuria and excessive thirst
Correct answer: A
Rationale: A serum sodium level of 185 mEq/L (185 mmol/L) is dangerously high and indicates severe dehydration, requiring immediate intervention to prevent neurological damage. The other options are not as critical as high serum sodium levels, which can lead to serious complications such as seizures, coma, and death if not promptly addressed. Dry skin with poor skin turgor and polyuria with excessive thirst are common findings in clients with Diabetes Insipidus and should be managed but do not pose an immediate threat to the client's life. An apical heart rate of 110 beats per minute may indicate tachycardia, which could be related to dehydration but is not as urgent as addressing the severe hypernatremia.
2. A client with chronic renal failure is receiving erythropoietin therapy. The nurse should assess the client for which of the following side effects?
- A. Hypotension.
- B. Hypertension.
- C. Hyperglycemia.
- D. Hypercalcemia.
Correct answer: B
Rationale: The correct answer is B: Hypertension. Erythropoietin therapy can lead to an increase in blood pressure, making hypertension a common side effect that the nurse should closely monitor. Hypotension (choice A) is not typically associated with erythropoietin therapy. Hyperglycemia (choice C) and hypercalcemia (choice D) are not commonly linked to erythropoietin therapy in clients with chronic renal failure, making them incorrect choices.
3. What is an expected outcome when a client is receiving an IV administration of furosemide?
- A. Increased blood pressure.
- B. Increased urine output.
- C. Decreased pain.
- D. Decreased premature ventricular contractions.
Correct answer: B
Rationale: The correct answer is B: Increased urine output. Furosemide is a loop diuretic that works by inhibiting the reabsorption of sodium and chloride in the ascending loop of Henle in the kidneys, leading to increased urine production. This diuretic effect helps to reduce fluid volume in the body, making it an expected outcome when a client is receiving furosemide. Choice A, increased blood pressure, is incorrect because furosemide typically causes a decrease in blood pressure due to its diuretic effect. Choice C, decreased pain, and choice D, decreased premature ventricular contractions, are unrelated to the pharmacological action of furosemide.
4. A client with polycystic kidney disease (PKD is being assessed by a nurse. Which assessment finding should prompt the nurse to immediately contact the healthcare provider?
- A. Flank pain
- B. Periorbital edema
- C. Bloody and cloudy urine
- D. Enlarged abdomen
Correct answer: B
Rationale: Periorbital edema would not typically be associated with polycystic kidney disease (PKD) and could indicate other underlying issues that require immediate attention. Flank pain and an enlarged abdomen are common findings in PKD due to kidney enlargement and displacement of other organs. Bloody or cloudy urine can result from cyst rupture or infection, which are expected in PKD. Therefore, periorbital edema is the most alarming finding in this scenario and warrants prompt notification of the healthcare provider.
5. Blood for arterial blood gas determinations is drawn from a client with pneumonia, and testing reveals a pH of 7.45, PCO2 of 30 mm Hg, and HCO3 of 19 mEq/L. The nurse interprets these results as indicative of:
- A. Compensated metabolic acidosis
- B. Compensated respiratory alkalosis
- C. Uncompensated metabolic alkalosis
- D. Uncompensated respiratory acidosis
Correct answer: B
Rationale: The correct answer is 'Compensated respiratory alkalosis.' In this case, the client's pH is within the normal range (7.35-7.45), indicating compensation. The low PCO2 (30 mm Hg) suggests respiratory alkalosis, while the low HCO3 (19 mEq/L) is also consistent with a compensatory response. Therefore, the client has a primary respiratory alkalosis that is being compensated for by metabolic acidosis. Choices A, C, and D are incorrect because they do not fit the pattern of the given blood gas values, which indicate respiratory alkalosis with metabolic compensation.
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