Nursing Elites

1. A client with nephrotic syndrome is being assessed by a nurse. For which clinical manifestations should the nurse assess? (Select all that apply.)

• A. Proteinuria
• B. Hypoalbuminemia
• C. Lipiduria
• D. All of the above

Correct answer: D

Rationale: Nephrotic syndrome is characterized by glomerular damage, leading to proteinuria (excessive protein in the urine), hypoalbuminemia (low levels of albumin in the blood), and lipiduria (lipids in the urine). These manifestations are key indicators of nephrotic syndrome. Edema, often severe, is also common due to decreased plasma oncotic pressure from hypoalbuminemia. The correct answer is 'All of the above' because all three manifestations are associated with nephrotic syndrome. Dehydration is not a typical finding in nephrotic syndrome as it is more commonly associated with fluid retention and edema. Dysuria is a symptom of cystitis, not nephrotic syndrome. CVA tenderness is more indicative of inflammatory changes in the kidney rather than nephrotic syndrome.

2. An older female client has normal saline infusing at 45 mL/hour. She complains of pain at the insertion site of the IV catheter. There is no redness or edema around the IV site. Which action should the nurse take?

• A. Determine which IV medications have recently been administered.
• B. Explain that without redness or edema, there is no need to re-start the IV.
• C. Consult with the healthcare provider about the best location to start a new IV.
• D. Convert the IV to a saline lock and continue to monitor the site.

Correct answer: D

Rationale: Converting the IV to a saline lock and continuing to monitor the site is the correct action in this scenario. When a client complains of pain at the IV insertion site without redness or edema, it may indicate phlebitis or irritation. Replacing the IV may not be necessary if there are no signs of infection or infiltration. Determining the IV medications administered or consulting with the healthcare provider to start a new IV are not immediate actions required for pain management at the insertion site. Therefore, the most appropriate intervention is to convert the IV to a saline lock and closely observe for any changes or complications.

3. What is the priority intervention for a patient with a suspected myocardial infarction (MI)?

• A. Administering oxygen.
• B. Administering nitroglycerin.
• C. Administering aspirin.
• D. Administering morphine.

Correct answer: A

Rationale: Administering oxygen is the priority intervention for a patient with a suspected myocardial infarction to improve oxygenation. Oxygen helps ensure an adequate oxygen supply to the heart muscle, reducing the workload on the heart. Nitroglycerin and aspirin are important interventions in the treatment of MI; however, oxygen administration takes precedence to ensure adequate oxygenation. Morphine may be considered for pain relief, but it is not the initial priority in the treatment of a suspected MI.

4. A CD4+ lymphocyte count is performed on a client infected with HIV. The results of the test indicate a CD4+ count of 450 cells/L. The nurse interprets this test result as indicating:

• A. Improvement in the client
• B. The need for antiretroviral therapy
• C. The need to discontinue antiretroviral therapy
• D. An effective response to the treatment for HIV

Correct answer: B

Rationale: A CD4+ count of 450 cells/L is below the normal range (500-1600 cells/mcL), indicating a decline in immune function in the client. Antiretroviral therapy is recommended when the CD4+ count falls below 500 cells/mcL or below 25%, or when the client displays symptoms of HIV. Therefore, the interpretation of this test result suggests that the client requires antiretroviral therapy to manage the HIV infection. Choices A, C, and D are incorrect because a CD4+ count of 450 cells/L does not signify improvement, discontinuation of therapy, or an effective response to treatment for HIV.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

• A. Failing eyesight causing an unsafe environment.
• B. Renal osteodystrophy due to chronic renal failure.
• C. Osteoporosis due to hormonal changes.
• D. Cardiovascular changes leading to small strokes impairing mental acuity.

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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