Nursing Elites

1. A multiparous client with active herpes lesions is admitted to the unit with spontaneous rupture of membranes. Which action should the nurse take?

• A. Obtain blood culture.
• B. Administer penicillin.
• C. Cover lesion with a dressing.
• D. Prepare her for cesarean section.

Correct answer: D

Rationale: Active herpes lesions at the time of delivery increase the risk of neonatal transmission. The most appropriate action in this scenario is to prepare the client for a cesarean section. A cesarean section is often recommended to reduce the risk of neonatal transmission of herpes simplex virus during delivery, especially when active lesions are present. This intervention helps minimize direct contact between the newborn and the infected genital tract secretions, thereby decreasing the risk of transmission.

2. During a prenatal visit, the LPN/LVN discusses with a client the effects of smoking on the fetus. When compared with nonsmokers, mothers who smoke during pregnancy tend to produce infants who have

• A. lower Apgar scores.
• B. lower birth weights.
• C. respiratory distress.
• D. a higher rate of congenital anomalies.

Correct answer: B

Rationale: When mothers smoke during pregnancy, it is associated with intrauterine growth restriction, which leads to lower birth weights in infants. Maternal smoking can restrict the flow of oxygen and nutrients to the fetus, affecting its growth and development. This can result in babies being born with lower birth weights, which can have various health implications for the newborn. Choices A, C, and D are incorrect as smoking during pregnancy is primarily linked to intrauterine growth restriction and lower birth weights in infants, rather than lower Apgar scores, respiratory distress, or a higher rate of congenital anomalies.

3. The client delivered hours ago and has a boggy uterus displaced above and to the right of the umbilicus. What action should the nurse take?

• A. Inspect the perineal pad.
• B. Encourage voiding.
• C. Monitor vital signs.
• D. Notify the healthcare provider.

Correct answer: B

Rationale: A boggy uterus that is displaced above and to the right of the umbilicus may indicate a full bladder, which can impede uterine contraction and lead to hemorrhage. Encouraging the client to void helps relieve pressure on the uterus, promoting better contraction and preventing postpartum hemorrhage.

4. A postpartum client who is Rh-negative refuses to receive RhoGAM after the delivery of an infant who is Rh-positive. Which information should the nurse provide this client?

• A. RhoGAM prevents maternal antibody formation for future Rh-positive babies.
• B. RhoGAM is not necessary unless all of her pregnancies are Rh-positive.
• C. The Rh-positive factor from the fetus threatens her blood cells.
• D. The mother should receive RhoGAM when the baby is Rh-negative.

Correct answer: A

Rationale: The correct answer is A. RhoGAM is administered to Rh-negative individuals after exposure to Rh-positive blood to prevent the development of antibodies that could harm future Rh-positive babies during subsequent pregnancies. By refusing RhoGAM after the delivery of an Rh-positive infant, the mother risks developing these antibodies, which could lead to hemolytic disease in future pregnancies with Rh-positive babies. Therefore, it is crucial for the nurse to explain to the client that receiving RhoGAM prevents the formation of maternal antibodies against Rh-positive blood, safeguarding the health of future babies. Choices B, C, and D are incorrect. Choice B is incorrect because RhoGAM is necessary after exposure to Rh-positive blood, regardless of the Rh status of future pregnancies. Choice C is incorrect as it does not accurately convey the purpose of RhoGAM administration. Choice D is incorrect because RhoGAM is specifically given after exposure to Rh-positive blood, not when the baby is Rh-negative.

5. When preparing a class on newborn care for expectant parents, what content should be taught concerning the newborn infant born at term gestation?

• A. Milia are white marks caused by sebaceous glands and typically resolve within 2 to 4 weeks.
• B. Meconium is the first stool and is typically dark green or black in color.
• C. Vernix caseosa is a white, cheesy substance mainly found in skin folds, providing a protective layer.
• D. Pseudostrabismus in newborns usually self-resolves without the need for intervention.

Correct answer: C

Rationale: Vernix caseosa is a white, cheesy substance that acts as a protective barrier on the skin of newborns, particularly present in skin folds. It helps to prevent dehydration and protect the delicate skin of the newborn from the amniotic fluid in utero. Educating expectant parents about the presence and function of vernix caseosa can help them understand the importance of its preservation during the immediate postnatal period. Choices A, B, and D are incorrect as they do not directly relate to the protective function of vernix caseosa in newborns. Milia are small, white bumps on the skin due to blocked oil glands, meconium is the first stool of a newborn and is typically dark green or black in color, and pseudostrabismus refers to false appearance of misalignment of the eyes, which usually resolves on its own without intervention.

Similar Questions