HESI RN
Biology Test
1. Why does ice have the capability of floating on water?
- A. It has a higher viscosity
- B. It has a different chemical composition
- C. It has a high specific heat
- D. It forms a lattice when freezing
Correct answer: D
Rationale: The correct answer is D. Ice forms a lattice structure when it freezes, which makes it less dense than liquid water, allowing it to float. Choice A is incorrect because viscosity refers to a fluid's resistance to flow and is not related to ice floating. Choice B is incorrect as ice and liquid water have the same chemical composition (H2O). Choice C is incorrect because the high specific heat of water is not the reason why ice floats.
2. Which of the following describes the set of metabolic reactions and processes that take place in the cells of organisms to convert biochemical energy from nutrients into adenosine triphosphate (ATP), and then release waste products?
- A. Cellular respiration
- B. Meiosis
- C. Photosynthesis
- D. Mitosis
Correct answer: A
Rationale: The correct answer is A: Cellular respiration. Cellular respiration is the process in cells that converts biochemical energy from nutrients into ATP and releases waste products. This process occurs in the mitochondria of the cell. Choice B, Meiosis, is a type of cell division that produces gametes with half the chromosome number. Choice C, Photosynthesis, is the process by which plants, algae, and some bacteria convert light energy into chemical energy to produce glucose. Choice D, Mitosis, is a type of cell division that results in two daughter cells with identical sets of chromosomes as the parent cell.
3. What do prokaryotic cells lack in comparison to eukaryotic cells?
- A. A defined nucleus and a series of membrane-bound organelles
- B. A defined nucleus and no membrane-bound organelles
- C. No defined nucleus and a series of membrane-bound organelles
- D. No defined nucleus and no membrane-bound organelles
Correct answer: D
Rationale: Prokaryotic cells are characterized by the absence of a defined nucleus and membrane-bound organelles. Choice A is incorrect because prokaryotic cells lack membrane-bound organelles. Choice B is incorrect because prokaryotic cells lack both a defined nucleus and membrane-bound organelles. Choice C is incorrect as prokaryotic cells have no defined nucleus. Therefore, the correct answer is D.
4. What are the nitrogenous bases of DNA?
- A. Adenine, cytosine, guanine, and thymine
- B. Adenine, guanine, and uracil
- C. Adenine, guanine, and thymine
- D. Adenine, cytosine, guanine, and uracil
Correct answer: A
Rationale: The correct answer is A: Adenine, cytosine, guanine, and thymine. These are the four nitrogenous bases found in DNA. Adenine pairs with thymine, and cytosine pairs with guanine, forming the complementary base pairs in the double helix structure of DNA. Choice B is incorrect because uracil is a nitrogenous base found in RNA, not DNA. Choice C is incorrect as it is missing cytosine, one of the four bases in DNA. Choice D is incorrect because uracil is not a nitrogenous base in DNA, and it also lacks thymine, which is essential for DNA structure.
5. Binary fission is a type of asexual reproduction. Which of the following occurs during the binary fission process?
- A. The chromosomes bind to the plasma membrane
- B. The chromosomes attach to the spindle formed along the axis
- C. The chromosomes gather in the center of the cell
- D. The chromosomes begin to separate
Correct answer: A
Rationale: The correct answer is A. In binary fission, the chromosomes bind to the plasma membrane before the cell splits into two. This initial step ensures that each daughter cell receives a complete set of genetic material. Choice B is incorrect because the spindle apparatus is characteristic of eukaryotic cell division (mitosis), not prokaryotic binary fission. Choice C is incorrect as chromosomes do not necessarily gather in the center of the cell during binary fission. Choice D is incorrect because the chromosomes do not begin to separate in binary fission; they replicate and then move to opposite ends of the cell before division.
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