HESI RN
HESI Medical Surgical Test Bank
1. Which client is at greatest risk for coronary artery disease?
- A. A 32-year-old female with mitral valve prolapse who quit smoking 10 years ago.
- B. A 43-year-old male with a family history of CAD and a cholesterol level of 158 (8.8 mmol/L).
- C. A 56-year-old male with an HDL of 60 (3.3 mmol/L) who takes atorvastatin.
- D. A 65-year-old female who is obese with an LDL of 188 (10.4 mmol/L).
Correct answer: D
Rationale: The 65-year-old female who is obese with a high LDL level of 188 (10.4 mmol/L) is at the greatest risk for coronary artery disease. Obesity and high LDL cholesterol levels are significant risk factors for developing coronary artery disease. While factors like mitral valve prolapse (choice A) and a family history of CAD (choice B) can contribute to the risk, they are not as significant as obesity and high LDL levels. Choice C, a 56-year-old male with high HDL and taking atorvastatin, is actually at lower risk due to the high HDL levels and being on statin therapy, which helps reduce cholesterol levels and lower the risk of coronary artery disease.
2. A client is vomiting. For which acid-base imbalance does the nurse assess the client?
- A. Metabolic acidosis
- B. Metabolic alkalosis
- C. Respiratory acidosis
- D. Respiratory alkalosis
Correct answer: B
Rationale: In a client who is vomiting, the loss of gastric fluid containing hydrochloric acid can lead to metabolic alkalosis. Metabolic alkalosis is caused by the loss of acids such as hydrochloric acid from the body. Therefore, in this scenario, the nurse should assess the client for metabolic alkalosis. Choices A, C, and D are incorrect because vomiting does not typically lead to metabolic acidosis, respiratory acidosis, or respiratory alkalosis.
3. In assessing cancer risk, which woman is at greatest risk of developing breast cancer?
- A. A 35-year-old multipara who never breastfed.
- B. A 50-year-old whose mother had unilateral breast cancer.
- C. A 55-year-old whose mother-in-law had bilateral breast cancer.
- D. A 20-year-old whose menarche occurred at age 9.
Correct answer: B
Rationale: The correct answer is B because family history of breast cancer, specifically in the mother, is a significant risk factor for developing breast cancer. The age of 50 is also a risk factor for breast cancer. Choice A is less likely as breastfeeding can actually reduce the risk of breast cancer. Choice C is less relevant since the risk is higher with a direct family member. Choice D, although early menarche is a risk factor, the age of the individual is much lower compared to the other age-related risk factors.
4. A client who experienced partial-thickness burns involving over 50% body surface area (BSA) 2 weeks ago has several open wounds and develops watery diarrhea. The client's blood pressure is 82/40 mmHg, and temperature is 96°F (36.6°C). Which action is most important for the nurse to take?
- A. Increase the room temperature.
- B. Assess the oxygen saturation.
- C. Continue to monitor vital signs.
- D. Notify the rapid response team.
Correct answer: D
Rationale: In this scenario, the client is presenting with signs of sepsis, such as hypotension, hypothermia, and a recent history of partial-thickness burns with open wounds. The development of watery diarrhea further raises suspicion for sepsis. With a blood pressure of 82/40 mmHg and a low temperature of 96°F (36.6°C), the nurse should recognize the potential for septic shock. Notifying the rapid response team is crucial in this situation as the client requires immediate intervention and management to prevent deterioration and address the underlying septic process. Increasing the room temperature (Choice A) is not the priority as the low body temperature is likely due to systemic vasodilation and not environmental factors. While assessing oxygen saturation (Choice B) is important, the client's hypotension and hypothermia take precedence. Continuing to monitor vital signs (Choice C) alone is insufficient given the critical condition of the client and the need for prompt action to address the sepsis and potential septic shock.
5. A nurse assesses a client who is recovering from a radical nephrectomy for renal cell carcinoma. The nurse notes that the client’s blood pressure has decreased from 134/90 to 100/56 mm Hg and urine output is 20 mL for this past hour. Which action should the nurse take?
- A. Position the client to lay on the surgical incision.
- B. Measure the specific gravity of the client’s urine.
- C. Administer intravenous pain medications.
- D. Assess the rate and quality of the client’s pulse.
Correct answer: D
Rationale: The nurse should first fully assess the client for signs of volume depletion and shock, and then notify the provider. The radical nature of the surgery and the proximity of the surgery to the adrenal gland put the client at risk for hemorrhage and adrenal insufficiency. Hypotension is a clinical manifestation associated with both hemorrhage and adrenal insufficiency. Hypotension is particularly dangerous for the remaining kidney, which must receive adequate perfusion to function effectively. Re-positioning the client, measuring specific gravity, and administering pain medication would not provide data necessary to make an appropriate clinical decision, nor are they appropriate interventions at this time.
Similar Questions
Access More Features
HESI RN Basic
$69.99/ 30 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access
HESI RN Premium
$149.99/ 90 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access