Nursing Elites

1. In a patient with chronic obstructive pulmonary disease (COPD), which of the following interventions is most important?

• A. Encouraging the patient to stop smoking.
• B. Administering bronchodilators.
• C. Monitoring oxygen saturation.
• D. Providing nutritional support.

Correct answer: C

Rationale: Monitoring oxygen saturation is the most important intervention in a patient with COPD because it helps assess the adequacy of oxygenation. In COPD, patients often have compromised lung function, leading to decreased oxygen levels in the blood. Monitoring oxygen saturation allows healthcare providers to promptly identify and address any potential hypoxemia, which is vital in managing COPD exacerbations. While encouraging the patient to stop smoking (Choice A) is critical for long-term management, monitoring oxygen saturation takes precedence in the immediate care of a COPD patient. Administering bronchodilators (Choice B) and providing nutritional support (Choice D) are important aspects of managing COPD but are secondary to monitoring oxygen saturation, which directly impacts the patient's oxygenation status.

2. A client is brought to the emergency department by a neighbor. The client is lethargic and has a fruity odor on the breath. The client’s arterial blood gas (ABG) results are pH 7.25, PCO2 34 mm Hg, PO2 86 mm Hg, HCO3 14 mEq/L. Which of the following acid-base disturbances does the nurse recognize in these results?

• A. Metabolic acidosis
• B. Metabolic alkalosis
• C. Respiratory acidosis
• D. Respiratory alkalosis

Correct answer: A

Rationale: The correct answer is 'Metabolic acidosis.' Metabolic acidosis is characterized by a low pH (<7.35) and a low bicarbonate level (HCO3 <22 mEq/L). In this case, the client's ABG results show a pH of 7.25 and an HCO3 level of 14 mEq/L, indicating metabolic acidosis. The PCO2 of 34 mm Hg is normal, ruling out respiratory acidosis or alkalosis. The PO2 of 86 mm Hg is also within the normal range and is not indicative of a respiratory problem. Therefore, the client is experiencing metabolic acidosis based on the ABG results provided.

3. What is the most common side effect of diuretics such as furosemide (Lasix)?

• A. Hypokalemia.
• B. Hyperkalemia.
• C. Hypernatremia.
• D. Hyponatremia.

Correct answer: A

Rationale: The correct answer is 'Hypokalemia.' Diuretics like furosemide increase the excretion of potassium, leading to hypokalemia as a common side effect. Hyperkalemia (choice B) is the opposite condition characterized by high potassium levels, which is not typically associated with furosemide use. Hypernatremia (choice C) is increased sodium levels, while hyponatremia (choice D) is decreased sodium levels, neither of which are the most common side effects of furosemide. Therefore, choice A is the best answer.

4. A client who is receiving chemotherapy asks the nurse, 'Why is so much of my hair falling out each day?' Which response by the nurse best explains the reason for alopecia?

• A. 'Chemotherapy affects the cells of the body that grow rapidly, both normal and malignant.'
• B. 'Alopecia is a common side effect you will experience during long-term steroid therapy.'
• C. 'Your hair will grow back completely after your course of chemotherapy is completed.'
• D. 'The chemotherapy causes permanent alterations in your hair follicles that lead to hair loss.'

Correct answer: A

Rationale: The correct answer is A: 'Chemotherapy affects the cells of the body that grow rapidly, both normal and malignant.' Chemotherapy targets rapidly dividing cells, which include not only cancer cells but also healthy cells like those in hair follicles. This leads to alopecia (hair loss) as a common side effect. Choice B is incorrect as alopecia is primarily associated with chemotherapy and not long-term steroid therapy. Choice C is incorrect because while hair may grow back after chemotherapy, it may not always be to the same extent or thickness. Choice D is incorrect as chemotherapy-induced hair loss is often temporary and reversible, not permanent alterations in hair follicles.

5. What is the priority intervention for a patient with a suspected myocardial infarction (MI)?

• A. Administering oxygen.
• B. Administering nitroglycerin.
• C. Administering aspirin.
• D. Administering morphine.

Correct answer: A

Rationale: Administering oxygen is the priority intervention for a patient with a suspected myocardial infarction to improve oxygenation. Oxygen helps ensure an adequate oxygen supply to the heart muscle, reducing the workload on the heart. Nitroglycerin and aspirin are important interventions in the treatment of MI; however, oxygen administration takes precedence to ensure adequate oxygenation. Morphine may be considered for pain relief, but it is not the initial priority in the treatment of a suspected MI.

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