in a patient with chronic obstructive pulmonary disease copd which of the following interventions is most important
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Nursing Elites

HESI RN

HESI Medical Surgical Practice Exam

1. In a patient with chronic obstructive pulmonary disease (COPD), which of the following interventions is most important?

Correct answer: C

Rationale: Monitoring oxygen saturation is the most important intervention in a patient with COPD because it helps assess the adequacy of oxygenation. In COPD, patients often have compromised lung function, leading to decreased oxygen levels in the blood. Monitoring oxygen saturation allows healthcare providers to promptly identify and address any potential hypoxemia, which is vital in managing COPD exacerbations. While encouraging the patient to stop smoking (Choice A) is critical for long-term management, monitoring oxygen saturation takes precedence in the immediate care of a COPD patient. Administering bronchodilators (Choice B) and providing nutritional support (Choice D) are important aspects of managing COPD but are secondary to monitoring oxygen saturation, which directly impacts the patient's oxygenation status.

2. The healthcare provider assesses a client with cirrhosis and finds 4+ pitting edema of the feet and legs, and massive ascites. Which mechanism contributes to edema and ascites in clients with cirrhosis?

Correct answer: D

Rationale: In clients with cirrhosis, hypoalbuminemia leads to decreased colloidal oncotic pressure. This reduction in oncotic pressure contributes to the development of edema in the feet and legs (pitting edema) and ascites in the abdomen. Hyperaldosteronism (choice A) would lead to sodium retention but is not the primary mechanism behind edema and ascites in cirrhosis. Decreased portacaval pressure with greater collateral circulation (choice B) is not directly related to the pathophysiology of edema and ascites in cirrhosis. Decreased renin-angiotensin response related to increased renal blood flow (choice C) does not play a significant role in the development of edema and ascites in cirrhosis compared to the impact of hypoalbuminemia on colloidal oncotic pressure.

3. The nurse is preparing to administer an antibiotic to a patient who has been receiving the antibiotic for 2 days after a culture was obtained. The nurse notes increased erythema and swelling, and the patient has a persistent high fever of 39°C. What is the nurse’s next action?

Correct answer: D

Rationale: In this scenario, the nurse is observing signs of a possible lack of response to the current antibiotic therapy, such as increased erythema, swelling, and persistent high fever. The next appropriate action for the nurse is to review the sensitivity results from the patient’s culture. This step is crucial to determine if the current antibiotic is effective against the causative organism. If the sensitivity results indicate resistance to the current antibiotic, the antibiotic should be discontinued, and the provider should be notified for a change in therapy. Contacting the provider to request another culture is not the immediate priority, as the existing culture results need to be reviewed first. Adding a second antibiotic should only be considered after confirming the sensitivity results, as unnecessary antibiotic use can lead to antimicrobial resistance.

4. A client admitted to the hospital with a diagnosis of acute pancreatitis has blood drawn for several serum laboratory tests. Which of the following serum amylase values, noted by the nurse reviewing the results, would be expected in this client at this time?

Correct answer: D

Rationale: The correct answer is D: "395 units/L." The normal serum amylase range is 25 to 151 units/L. In acute pancreatitis, the amylase level is greatly increased, typically exceeding the upper limit of the normal range. Choices A, B, and C fall within the normal range of serum amylase levels and would not be expected in a client with acute pancreatitis.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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