HESI RN
HESI Medical Surgical Assignment Exam
1. A client has the following arterial blood gas (ABG) results: pH 7.51, PCO2 31 mm Hg, PO2 94 mm Hg, HCO3 24 mEq/L. Which of the following acid-base disturbances does the nurse recognize in these results?
- A. Metabolic acidosis
- B. Metabolic alkalosis
- C. Respiratory acidosis
- D. Respiratory alkalosis
Correct answer: D
Rationale: The ABG results show a pH above the normal range (7.35-7.45) and a decreased PCO2, indicating respiratory alkalosis. In respiratory alkalosis, the pH is increased and the PCO2 is decreased. Metabolic acidosis (choice A) would present with a low pH and low HCO3 levels. Metabolic alkalosis (choice B) would show an increased pH and HCO3 levels. Respiratory acidosis (choice C) would have a low pH and an increased PCO2.
2. Prior to administering tissue plasminogen activator (t-PA), the nurse should assess the client for which of the following contraindications to administering the drug?
- A. Age over 60 years.
- B. History of cerebral hemorrhage.
- C. History of heart failure.
- D. Cigarette smoking.
Correct answer: B
Rationale: The correct answer is B: History of cerebral hemorrhage. A history of cerebral hemorrhage is a contraindication to t-PA administration because of the increased risk of bleeding. Choices A, C, and D are incorrect. Age over 60 years is not a contraindication for t-PA administration. While older age may pose some risks, it is not an absolute contraindication. History of heart failure is not a direct contraindication to t-PA administration. Cigarette smoking, while a risk factor for cardiovascular disease, is not a specific contraindication for t-PA administration.
3. What is the most common cause of coronary artery disease?
- A. Atherosclerosis.
- B. Hyperlipidemia.
- C. Diabetes.
- D. Smoking.
Correct answer: A
Rationale: The correct answer is Atherosclerosis. It is the primary cause of coronary artery disease, as it involves the buildup of plaque in the arteries, restricting blood flow to the heart. Hyperlipidemia (choice B) contributes to atherosclerosis by increasing cholesterol levels in the blood but is not the direct cause of coronary artery disease. Diabetes (choice C) can accelerate atherosclerosis due to high blood sugar levels, but it is not the most common cause. Smoking (choice D) is a significant risk factor for developing coronary artery disease but is not the primary cause.
4. A nurse reviews the urinalysis of a client and notes the presence of glucose. Which action should the nurse take?
- A. Document findings and continue to monitor the client.
- B. Contact the provider and recommend a 24-hour urine test.
- C. Review the client’s recent dietary selections.
- D. Perform a capillary artery glucose assessment.
Correct answer: D
Rationale: Glucose normally is not found in the urine. The normal renal threshold for glucose is about 220 mg/dL, which means that a person whose blood glucose is less than 220 mg/dL will not have glucose in the urine. A positive finding for glucose on urinalysis indicates high blood sugar. The most appropriate action would be to perform a capillary artery glucose assessment. The client needs further evaluation for this abnormal result; therefore, documenting and continuing to monitor is not appropriate. Requesting a 24-hour urine test or reviewing the client’s dietary selections will not assist the nurse to make a clinical decision related to this abnormality.
5. The nurse is caring for several patients who are receiving antibiotics. Which order will the nurse question?
- A. Azithromycin (Zithromax) 500 mg IV in 500 mL of fluid
- B. Azithromycin (Zithromax) 500 mg PO once daily
- C. Erythromycin 300 mg IM QID
- D. Erythromycin 300 mg PO QID
Correct answer: C
Rationale: The nurse should question the order for Erythromycin 300 mg IM QID. Erythromycin and other macrolides should not be given intramuscularly because they cause painful tissue irritation. Options A and B are correct routes for Azithromycin, either intravenously or orally. Option D is a correct route for Erythromycin, which is orally.
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