Nursing Elites

1. The nurse is planning discharge instructions for the mother of a child following orchiopexy, which was performed on an outpatient basis. Which is a priority in the plan of care?

• A. Wound care
• B. Pain control measures
• C. Measurement of intake
• D. Cold and heat applications

Correct answer: A

Rationale: Following orchiopexy, the priority in the plan of care for the child's mother is wound care. The most common complications associated with orchiopexy are bleeding and infection. Discharge instructions should focus on demonstrating wound cleansing and dressing, and teaching parents to recognize signs of infection like redness, warmth, swelling, or discharge. It is crucial to prevent movement of the testicles and avoid contamination of the suture line. While analgesics may be prescribed, pain control measures are not the priority among the options presented. Measurement of intake is not essential as the child is likely to resume normal eating habits. Cold and heat applications are not typical prescribed treatments for post-orchiopexy care.

2. Which of the following glands found in the skin secretes a liquid called Sebum?

• A. Apocrine Glands
• B. Sebaceous Glands
• C. Lacrimal Glands
• D. Sweat Glands

Correct answer: B

Rationale: Sebum is a liquid secreted by glands in the skin known as sebaceous glands. Sebum's primary function is to lubricate the skin and help maintain its integrity. Apocrine glands secrete a different type of sweat that is odorless but can develop an odor when combined with bacteria on the skin. Lacrimal glands produce tears to keep the eyes moist, and sweat glands secrete sweat to regulate body temperature through evaporation. Therefore, the correct answer is Sebaceous Glands because they specifically secrete sebum, distinguishing them from the other gland types mentioned.

3. The nurse develops a plan of care to prevent aspiration in a high-risk patient. Which nursing action will be most effective?

• A. Turn and reposition immobile patients at least every 2 hours.
• B. Place patients with altered consciousness in side-lying positions.
• C. Monitor for respiratory symptoms in immunosuppressed patients.
• D. Insert nasogastric tube for feedings in patients with swallowing problems.

Correct answer: B

Rationale: To prevent aspiration in a high-risk patient, the most effective nursing action is to place patients with altered consciousness in side-lying positions. This position helps decrease the risk of aspiration as it prevents pooling of secretions and facilitates drainage. Turning and repositioning immobile patients every 2 hours is essential for preventing pressure ulcers and improving circulation but does not directly address the risk of aspiration. Monitoring respiratory symptoms in immunosuppressed patients is crucial to detect pneumonia early, but it does not directly prevent aspiration. Inserting a nasogastric tube for feedings in patients with swallowing problems may be necessary for nutritional support but does not address the risk of aspiration directly. Patients at high risk for aspiration include those with altered consciousness, difficulty swallowing, and those with nasogastric intubation, among others. Placing patients with altered consciousness in a side-lying position is a key intervention to reduce the risk of aspiration in this population. Other high-risk groups for aspiration include those who are seriously ill, have poor dentition, or are on acid-reducing medications.

4. The healthcare provider calculates the IV flow rate for a patient receiving lactated Ringer's solution. The patient needs to receive 2000mL of Lactated Ringer's over 36 hours. The IV infusion set has a drop factor of 15 drops per milliliter. How many drops per minute should the healthcare provider set the IV to deliver?

• A. 8
• B. 10
• C. 14
• D. 18

Correct answer: C

Rationale: To determine the drops per minute, we use the formula Drops Per Minute = (Milliliters x Drop Factor) / Time in Minutes. In this case, Drops Per Minute = (2000mL x 15 drops/mL) / (36 hours x 60 minutes/hour) = 30000 / 2160 = 13.89 (approximately 14). Therefore, the correct answer is 14 drops per minute. Choice A (8), Choice B (10), and Choice D (18) are incorrect as they do not correctly calculate the drops per minute based on the given information.

5. A patient in metabolic alkalosis is admitted to the emergency department, and pulse oximetry indicates that the O2 saturation is 94%. Which action should the nurse take next?

• A. Administer bicarbonate.
• B. Complete a head-to-toe assessment.
• C. Place the patient on high-flow oxygen.
• D. Obtain repeat arterial blood gases (ABGs).

Correct answer: C

Rationale: In a patient with metabolic alkalosis and an O2 saturation of 94%, placing the patient on high-flow oxygen is the correct action. Even though the O2 saturation seems adequate, metabolic alkalosis causes a left shift in the oxyhemoglobin dissociation curve, reducing oxygen delivery to tissues. Therefore, providing high-flow oxygen can help compensate for this. Administering bicarbonate would exacerbate the alkalosis. While completing a head-to-toe assessment and obtaining repeat ABGs are important interventions, the priority in this scenario is to improve oxygen delivery by placing the patient on high-flow oxygen.

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