Nursing Elites

1. Why is the combination drug trimethoprim-sulfamethoxazole (TMP-SMX) necessary?

• A. To broaden the antibacterial spectrum.
• B. To decrease bacterial resistance.
• C. To improve the taste.
• D. To minimize toxic effects.

Correct answer: B

Rationale: The correct answer is B: To decrease bacterial resistance. Trimethoprim-sulfamethoxazole (TMP-SMX) is a combination drug used to prevent bacterial resistance to sulfonamides. It works by targeting different steps in the bacterial metabolic pathway, making it harder for bacteria to develop resistance. Choice A is incorrect because the combination does not broaden the antibacterial spectrum; instead, it enhances effectiveness against specific bacteria. Choice C is incorrect as taste improvement is not the primary reason for combining these drugs. Choice D is incorrect because while combination therapy can sometimes help minimize toxic effects, the primary purpose in this case is to address bacterial resistance.

2. A client is returning home after arthroscopy of the shoulder. The nurse should tell the client:

• A. To resume full activity the next day
• B. Not to eat or drink anything until the next morning
• C. To keep the shoulder completely immobilized for the rest of the day
• D. To report to the physician the development of fever or redness and heat at the site

Correct answer: D

Rationale: After arthroscopy, it is important for the client to report any signs of infection, such as the development of fever or redness and heat at the site, to the physician promptly. Options A, B, and C are incorrect. The client should not resume full activity the next day as rest and limited movement are usually recommended post-arthroscopy. It is not necessary to withhold food or fluids until the next morning; the client may resume the usual diet immediately unless otherwise instructed. While immobilization may be recommended for a period, keeping the shoulder completely immobilized for the rest of the day is not typically necessary post-arthroscopy.

3. The patient weighs 75 kg and is receiving IV fluids at a rate of 50 mL/hour, having consumed 100 mL orally in the past 24 hours. What action will the nurse take?

• A. Contact the provider to ask about increasing the IV rate to 90 mL/hour.
• B. Discuss with the provider the need to increase the IV rate to 150 mL/hour.
• C. Encourage the patient to drink more water so the IV can be discontinued.
• D. Instruct the patient to drink 250 mL of water every 8 hours.

Correct answer: A

Rationale: The recommended daily fluid intake for adults is 30 to 40 mL/kg/day. For a patient weighing 75 kg, the minimum intake should be 2250 mL/day. The patient is currently receiving 1200 mL IV and 100 mL orally, totaling 1300 mL. Increasing the IV rate to 90 mL/hour would provide a total of 2160 mL, which could meet the patient's needs if oral intake continues. Option B suggests increasing the IV rate to 150 mL/hour, resulting in an excessive fluid intake of 3600 mL/day, surpassing the recommended amount. Option C, encouraging increased fluid intake, is not recommended as the patient is already struggling with fluid intake. Option D, instructing the patient to drink 250 mL of water every 8 hours, would still fall short of the required fluid intake of 2250 mL/day.

4. What is the priority intervention for a patient with a suspected myocardial infarction (MI)?

• A. Administering oxygen.
• B. Administering nitroglycerin.
• C. Administering aspirin.
• D. Administering morphine.

Correct answer: A

Rationale: Administering oxygen is the priority intervention for a patient with a suspected myocardial infarction to improve oxygenation. Oxygen helps ensure an adequate oxygen supply to the heart muscle, reducing the workload on the heart. Nitroglycerin and aspirin are important interventions in the treatment of MI; however, oxygen administration takes precedence to ensure adequate oxygenation. Morphine may be considered for pain relief, but it is not the initial priority in the treatment of a suspected MI.

5. The client is being educated by the nurse on home blood glucose monitoring. Which of the following blood glucose measurements indicates hypoglycemia?

• A. 59 mg/dL (3.3 mmol/L)
• B. 75 mg/dL (4.2 mmol/L)
• C. 108 mg/dL (6 mmol/L)
• D. 119 mg/dL (6.6 mmol/L)

Correct answer: A

Rationale: A blood glucose level of 59 mg/dL (3.3 mmol/L) is considered hypoglycemia, which is an abnormally low blood sugar level. This level requires immediate attention as it can lead to symptoms such as confusion, shakiness, and even loss of consciousness if left untreated. Choices B, C, and D have blood glucose levels within the normal range or slightly higher, indicating euglycemia or normal blood sugar levels, and not hypoglycemia.

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