Nursing Elites

1. A client with type 1 diabetes mellitus has a blood glucose level of 620 mg/dL. After the nurse calls the physician to report the finding and monitors the client closely for:

• A. Metabolic acidosis
• B. Metabolic alkalosis
• C. Respiratory acidosis
• D. Respiratory alkalosis

Correct answer: A

Rationale: In the scenario described, a client with a blood glucose level of 620 mg/dL and type 1 diabetes mellitus is at risk of developing metabolic acidosis. In type 1 diabetes, the lack of sufficient circulating insulin leads to an increase in blood glucose levels. As the body cells utilize all available glucose, the breakdown of fats for energy results in the production of ketones, leading to metabolic acidosis. Metabolic alkalosis, respiratory acidosis, and respiratory alkalosis are not typically associated with uncontrolled type 1 diabetes. Metabolic alkalosis is more commonly linked to conditions such as vomiting or excessive diuretic use, while respiratory acidosis and respiratory alkalosis are related to respiratory system imbalances in carbon dioxide levels.

2. What is the most important content for the nurse to include in discharge teaching for a 51-year-old truck driver who smokes two packs of cigarettes a day, is 30 pounds overweight, and has been diagnosed with a gastric ulcer?

• A. Information about smoking cessation.
• B. Diet instructions for a low-residue diet.
• C. Instructions on a weight-loss program.
• D. The importance of increasing milk in the diet.

Correct answer: A

Rationale: The correct answer is A: Information about smoking cessation. Smoking is a significant risk factor for ulcer formation. It is crucial for the nurse to include smoking cessation information in the discharge teaching to help manage the gastric ulcer and prevent further complications. Choices B, C, and D are less relevant in this scenario. While diet modifications may be beneficial, addressing smoking cessation takes precedence due to its direct correlation with ulcer development.

3. The nurse explains to the client with Hodgkin's disease that a bone marrow biopsy will be taken after the aspiration. What should the nurse explain about the biopsy?

• A. The biopsy will confirm the diagnosis of Hodgkin's disease.
• B. The biopsy will show the extent of the disease in the bones.
• C. The biopsy will be done to check for infection in the bones.
• D. The biopsy will help determine the best treatment for the disease.

Correct answer: D

Rationale: A bone marrow biopsy helps determine the best treatment plan for Hodgkin's disease by providing crucial information about the extent and nature of the disease. While confirming the diagnosis is important, the primary purpose of the biopsy in this case is to guide treatment decisions. The biopsy is not primarily for assessing the extent of the disease in the bones or checking for infections in the bones.

4. A client with autosomal dominant polycystic kidney disease (ADPKD) asks, “Will my children develop this disease?” How should the nurse respond?

• A. No genetic link is known, so your children are not at increased risk.
• B. Your sons will develop this disease because it has a sex-linked gene.
• C. Only if both you and your spouse are carriers of this disease.
• D. Each of your children has a 50% risk of having ADPKD.

Correct answer: D

Rationale: Children whose parent has the autosomal dominant form of PKD have a 50% chance of inheriting the gene that causes the disease. ADPKD is transmitted as an autosomal dominant trait and therefore is not gender-specific. Both parents do not need to have this disorder. Choice A is incorrect because ADPKD has a known genetic link and a definitive mode of inheritance. Choice B is incorrect as ADPKD is not sex-linked but autosomal dominant. Choice C is incorrect because ADPKD follows an autosomal dominant inheritance pattern and does not require both parents to be carriers for the child to inherit the disease.

5. A healthcare professional assesses clients on the medical-surgical unit. Which client is at greatest risk for the development of bacterial cystitis?

• A. A 36-year-old female who has never been pregnant
• B. A 42-year-old male who is prescribed cyclophosphamide
• C. A 58-year-old female who is not taking estrogen replacement
• D. A 77-year-old male with mild congestive heart failure

Correct answer: C

Rationale: Females are at higher risk of developing bacterial cystitis due to their shorter urethra compared to males. Postmenopausal women not on estrogen replacement therapy are particularly susceptible to cystitis because of changes in vaginal and urethral cells. This increases the risk of bacterial infection. The other options do not have the same level of risk as the postmenopausal woman not using hormone replacement therapy. A never-pregnant middle-aged woman does not have the same increased risk as a postmenopausal woman with hormonal changes.

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