Nursing Elites

1. A child is diagnosed with a Greenstick Fracture. Which of the following most accurately describes the broken bone?

• A. compound fracture of the fibula
• B. a partial break in a long bone
• C. fracture of the growth plate of the ulna near the wrist
• D. Colles fracture of the tibia

Correct answer: B

Rationale: A Greenstick Fracture is commonly found in children due to their bones being more flexible. This type of fracture occurs when a bone bends and partially breaks, resembling what happens when a green stick from a tree is bent in half. Therefore, the most accurate description of a Greenstick Fracture is 'a partial break in a long bone.' Choice A, 'compound fracture of the fibula,' is incorrect as a Greenstick Fracture is not a compound fracture. Choice C, 'fracture of the growth plate of the ulna near the wrist,' is incorrect as it describes a different type of fracture. Choice D, 'Colles fracture of the tibia,' is incorrect as it refers to a specific type of fracture in a different bone.

2. Which patient is at risk for developing oral candidiasis, a type of stomatitis?

• A. A 77-year-old woman in a long-term care facility taking an antibiotic
• B. A 35-year-old man who has had HIV for 6 years
• C. A 40-year-old man who is undergoing chemotherapy
• D. An 80-year-old woman with dentures

Correct answer: A

Rationale: The correct answer is a 77-year-old woman in a long-term care facility taking an antibiotic. This patient has multiple risk factors for developing oral candidiasis, including older age, being in a long-term care facility, and taking antibiotics. Candidiasis can be caused by long-term antibiotic therapy, immunosuppressive therapy (such as chemotherapy), older age, living in a long-term care facility, diabetes, having dentures, and poor oral hygiene. Choices B, C, and D are less likely to be at high risk for oral candidiasis compared to the correct answer.

3. During your evaluation of a 14-year-old girl with a BMI of 18, she reports inability to eat, induced vomiting, and severe constipation. Which of the following would you most likely suspect?

• A. Multiple sclerosis
• B. Anorexia nervosa
• C. Bulimia nervosa
• D. Systemic sclerosis

Correct answer: B

Rationale: The clinical presentation described in the question is highly suggestive of anorexia nervosa. Anorexia nervosa is characterized by self-imposed starvation due to a distorted body image and an intense fear of gaining weight, even when the individual is underweight. The patient's symptoms of inability to eat, induced vomiting, and severe constipation align with the behavior seen in anorexia nervosa, including restrictive eating patterns and purging behaviors. Multiple sclerosis (Choice A) is a neurological disorder, not associated with the described symptoms. Bulimia nervosa (Choice C) typically involves binge eating followed by purging behaviors, which is different from the described primary restriction seen in anorexia nervosa. Systemic sclerosis (Choice D) is a connective tissue disorder and is not related to the symptoms of self-induced vomiting and severe constipation reported in this case.

4. Which laboratory test result should the nurse monitor to evaluate the effects of therapy for a 62-year-old female patient with acute pancreatitis?

• A. Calcium
• B. Bilirubin
• C. Amylase
• D. Potassium

Correct answer: C

Rationale: The correct answer is C: Amylase. In acute pancreatitis, amylase levels are typically elevated. Monitoring amylase levels helps assess the effectiveness of therapy in managing the condition. Elevated amylase is a key indicator of pancreatic inflammation. Calcium (Choice A) levels may be affected in pancreatitis, but they are not the primary indicator for evaluating therapy effectiveness. Bilirubin (Choice B) and Potassium (Choice D) levels may also be altered in pancreatitis, but they are not specific markers for monitoring therapy response in acute pancreatitis.

5. A diabetic patient's arterial blood gas (ABG) results are pH 7.28; PaCO2 34 mm Hg; PaO2 85 mm Hg; HCO3 18 mEq/L. The nurse would expect which finding?

• A. Intercostal retractions
• B. Kussmaul respirations
• C. Low oxygen saturation (SpO2)
• D. Decreased venous O2 pressure

Correct answer: B

Rationale: Kussmaul respirations (deep and rapid) are a compensatory mechanism for metabolic acidosis. The low pH and low bicarbonate levels indicate metabolic acidosis. Intercostal retractions, low oxygen saturation, and decreased venous O2 pressure are not associated with acidosis. Intercostal retractions typically occur in respiratory distress, while low oxygen saturation and decreased venous O2 pressure are more related to respiratory or circulatory issues, not metabolic acidosis.

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