Nursing Elites

1. Which of the answer choices is an effective revision of the ambiguous sentence below? Tanya told her sister to tell her boyfriend Joe to call her as soon as he got home.

• A. Tanya's sister said, 'Tell Joe to call me as soon as he gets home.'
• B. Her sister told her boyfriend Joe to call Tanya as soon as he got home.
• C. Tanya said to her sister, 'Tell your boyfriend Joe to call me as soon as he gets home.'
• D. Tanya told her sister, 'Joe should call me as soon as he gets home.'

Correct answer: C

Rationale: The correct answer, option C, effectively clarifies the communication structure by specifying who is communicating with whom and when. Tanya instructs her sister to convey a message to her boyfriend Joe, requesting him to call Tanya upon his arrival home. This revision removes the ambiguity present in the original sentence. Option A is incorrect as it introduces unnecessary complexity and alters the original meaning. Option B is incorrect as it misinterprets the relationships among the individuals involved. Option D is incorrect as it changes the dynamics of the communication and does not address the ambiguity in the original sentence.

2. Divide 4/3 by 9/13 and reduce the fraction.

• A. 52/27
• B. 51/27
• C. 52/29
• D. 51/29

Correct answer: A

Rationale: To divide fractions, you multiply the first fraction by the reciprocal of the second fraction. So, (4/3) ÷ (9/13) = (4/3) * (13/9) = 52/27. This fraction is already in its reduced form, making choice A the correct answer. Choices B, C, and D are incorrect as they do not represent the correct result of dividing the fractions 4/3 by 9/13.

3. As part of a study, a set of patients will be divided into three groups. 4/15 of the patients will be in Group Alpha, 2/5 in Group Beta, and 1/3 in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.

• A. Group Alpha, Group Beta, Group Gamma
• B. Group Alpha, Group Gamma, Group Beta
• C. Group Gamma, Group Alpha, Group Beta
• D. Group Alpha, Group Beta, Group Gamma

Correct answer: B

Rationale: The correct order is Group Alpha, Group Gamma, Group Beta based on the common denominators of the fractions. To determine the order from smallest to largest, compare the fractions' numerators since the denominators are different. Group Alpha has 4/15 patients, Group Gamma has 1/3 patients, and Group Beta has 2/5 patients. Comparing the fractions' numerators, the order from smallest to largest is Group Alpha (4), Group Gamma (1), and Group Beta (2). Therefore, the correct order is Group Alpha, Group Gamma, Group Beta. Choice A is incorrect as it lists Group Beta before Group Gamma. Choice C is incorrect as it lists Group Gamma before Group Alpha. Choice D is incorrect as it lists Group Beta before Group Gamma, which is not in ascending order based on the number of patients.

4. An element with atomic number 26 and mass number 56 is most likely to be:

• A. Iron (Fe)
• B. Cobalt (Co)
• C. Nickel (Ni)
• D. Manganese (Mn)

Correct answer: A

Rationale: The element with atomic number 26 and mass number 56 corresponds to Iron (Fe). Iron has 26 protons, which aligns with the given atomic number, and Fe-56 has 26 neutrons, which aligns with the given mass number. This confirms that Iron (Fe) is the correct answer. Cobalt (Co), Nickel (Ni), and Manganese (Mn) have different atomic numbers and mass numbers, so they are not the correct choices in this scenario.

5. How do you find the least common multiple?

• A. List all multiples of the numbers, then find the smallest common one
• B. List all factors of the numbers, then find the largest common one
• C. Divide the largest number by the smallest
• D. Multiply the two numbers together

Correct answer: A

Rationale: The correct way to find the least common multiple is to list all the multiples of each number and then identify the smallest common multiple. Choice A is correct because it describes the correct process. Listing factors, as suggested in choice B, helps in finding the greatest common factor, not the least common multiple. Dividing the largest number by the smallest, as mentioned in choice C, does not help find the least common multiple. Multiplying the two numbers together, as stated in choice D, results in their least common multiple when the numbers have no common factors.

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