Nursing Elites

1. What is the medical term for a urinary tract infection (UTI)?

• A. Nephritis
• B. Cystitis
• C. Urethritis
• D. All of the above

Correct answer: B

Rationale: The medical term specifically used to refer to a urinary tract infection (UTI) that affects the bladder is cystitis. Nephritis refers to inflammation of the kidneys, and urethritis refers to inflammation of the urethra. As such, cystitis is the correct term for a UTI, making choice B the right answer. Choices A, C, and D are incorrect because they refer to different conditions affecting the urinary system.

2. What is 0.5 liters in milliliters?

• A. 50 ml
• B. 500 ml
• C. 5 ml
• D. 0.5 ml

Correct answer: B

Rationale: 0.5 liters is equivalent to 500 milliliters. To convert liters to milliliters, you multiply by 1000 since 1 liter equals 1000 milliliters. Therefore, the correct answer is 500 ml (0.5 * 1000 = 500). Choices A, C, and D are incorrect because they do not correctly convert 0.5 liters to milliliters.

3. How many grams of solid CaCO3 are needed to make 600 mL of a 35 M solution? The atomic masses for the elements are as follows: Ca = 40.1 g/mol; C = 12.01 g/mol; O = 16.00 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: 1. First, calculate the molar mass of CaCO3 by adding the atomic masses of Ca, C, and 3 O atoms: 40.1 + 12.01 + (3 * 16.00) = 100.13 g/mol. 2. Calculate the number of moles in 600 mL of a 35 M solution: 600 mL * 35 mol/L = 21,000 mmol. 3. Convert moles to grams using the molar mass of CaCO3: 21,000 mmol * (100.13 g/mol / 1000 mmol/mol) = 2,102.73 g. 4. Therefore, you would need 19.7 g of solid CaCO3 to make 600 mL of a 35 M solution.

4. What is the process by which simple cells become highly specialized cells?

• A. Cellular complication
• B. Cellular specialization
• C. Cellular differentiation
• D. Cellular modification

Correct answer: C

Rationale: The correct answer is 'Cellular differentiation'. Cellular differentiation is the process by which simple cells become highly specialized cells. During cellular differentiation, cells acquire specific structures and functions that allow them to perform particular roles within an organism. This process involves the activation and silencing of specific genes, leading to the development of various cell types with distinct characteristics and functions. 'Cellular complication' (Choice A) is incorrect as it does not describe the specific process of cells becoming specialized. 'Cellular specialization' (Choice B) is not the most precise term for the process, as it does not capture the transformation from simple cells to specialized cells. 'Cellular modification' (Choice D) is incorrect as it is a vague term that does not specifically refer to the process of cellular specialization.

5. Histograms use ________, and bar graphs do not.

• A. Ranges
• B. Categories
• C. Labels
• D. Percentages

Correct answer: A

Rationale: Correct Answer: Ranges. Histograms utilize ranges (intervals) to display the frequency distribution of continuous data, highlighting the frequency of values falling within each interval. Bar graphs, on the other hand, represent discrete data using separate and distinct bars to show comparisons between different categories or groups. Choice B (Categories) is incorrect because both histograms and bar graphs can display data based on categories, but histograms use ranges to group continuous data. Choice C (Labels) is incorrect as both types of graphs can have labels to provide context and information. Choice D (Percentages) is incorrect because percentages can be used in both histograms and bar graphs to show proportions, but they are not a defining feature that distinguishes histograms from bar graphs.

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