Nursing Elites

1. Based on Gemma's preferences and limited time, which of the following travel guides will be best for her?

• A. Exploring the Hawaiian Islands: The Best Waterfalls on the Big Island and Maui
• B. Na Pali: The Two-Day Hike That Changes Everything
• C. Pineapples, Taro, and Roasted Pigs: A Dining Guide to Hawaii
• D. The Top Ten: Beaches, Restaurants, and Sightseeing in Honolulu and on Oahu

Correct answer: A

Rationale: Given Gemma's goal of seeing as much as possible in a short time while enjoying outdoor activities and nature, the best travel guide for her would be 'Exploring the Hawaiian Islands: The Best Waterfalls on the Big Island and Maui.' This guide aligns with her interest in outdoor activities and waterfalls, making it the ideal choice to enhance her trip experience. Choice B, 'Na Pali: The Two-Day Hike That Changes Everything,' focuses on a specific hike and may not cover a broad range of attractions Gemma wants to explore. Choice C, 'Pineapples, Taro, and Roasted Pigs: A Dining Guide to Hawaii,' is more food-oriented and doesn't cater to Gemma's interest in outdoor activities. Choice D, 'The Top Ten: Beaches, Restaurants, and Sightseeing in Honolulu and on Oahu,' while offering a variety of attractions, doesn't specifically target Gemma's interest in exploring waterfalls and the natural beauty of Hawaii as she desires.

2. How do spindle fiber dynamics and microtubule attachment regulate cell cycle checkpoints?

• A. Misaligned chromosomes fail to attach to microtubules, triggering a delay in anaphase onset.
• B. The presence of unattached kinetochores on the centromeres sends a signal to pause cell cycle progression.
• C. Microtubule instability and rapid depolymerization lead to the activation of checkpoint proteins.
• D. All of the above.

Correct answer: D

Rationale: A) Misaligned chromosomes fail to attach to microtubules, triggering a delay in anaphase onset: Proper attachment of chromosomes to spindle fibers is essential for accurate segregation of genetic material during cell division. Misaligned chromosomes that fail to attach to microtubules can lead to delays in anaphase onset, allowing the cell to correct errors before proceeding with division. B) The presence of unattached kinetochores on the centromeres sends a signal to pause cell cycle progression: Kinetochores at the centromeres help attach chromosomes to spindle fibers. When kinetochores are unattached or improperly attached to microtubules, they signal the cell to pause cell cycle progression, ensuring proper chromosome alignment before division. C) Microtubule instability and rapid depolymerization lead to the activation of checkpoint proteins: While microtubule dynamics are crucial for cell division, microtubule instability and rapid depolymerization can disrupt chromosome attachment. However, this mechanism is not directly related to the activation of cell cycle checkpoint proteins, making this statement incorrect. Therefore, choices A and B accurately describe how spindle fiber dynamics and microtubule attachment regulate cell cycle checkpoints, making option D the correct answer.

3. When testing how quickly a rat dies based on the amount of poison it eats, which of the following is the independent variable and which is the dependent variable?

• A. How quickly the rat dies is the independent variable; the amount of poison is the dependent variable.
• B. The amount of poison is the independent variable; how quickly the rat dies is the dependent variable.
• C. Whether the rat eats the poison is the independent variable; how quickly the rat dies is the dependent variable.
• D. The cage the rat is kept in is the independent variable; the amount of poison is the dependent variable.

Correct answer: B

Rationale: The correct answer is B. In this experiment, the independent variable is the amount of poison because it is what is being manipulated by the researcher. The dependent variable is how quickly the rat dies, as it is the outcome that is being measured based on the different amounts of poison administered. Choice A is incorrect because the independent variable should be what is being manipulated or changed, which is the amount of poison in this case. Choice C is incorrect because whether the rat eats the poison is not being varied or controlled by the researcher. Choice D is incorrect because the cage the rat is kept in is not relevant to the relationship being studied between the amount of poison and the rat's survival time.

4. What are the finger-like projections that increase the surface area for absorption in the small intestine called?

• A. Crypts of Lieberkühn
• B. Goblet cells
• C. Villi
• D. Paneth cells

Correct answer: C

Rationale: A) Crypts of Lieberkühn are small pits in the lining of the small intestine that contain cells involved in the production of intestinal juices, but they do not increase the surface area for absorption. B) Goblet cells are specialized cells that secrete mucus to protect the lining of the digestive tract, but they do not increase the surface area for absorption. C) Villi are finger-like projections in the small intestine that increase the surface area available for nutrient absorption. Each villus contains blood vessels and lacteals (lymphatic vessels) that help absorb nutrients from digested food. D) Paneth cells are specialized cells found in the small intestine that secrete antimicrobial substances, but they do not increase the surface area for absorption.

5. What is the overall median of Dwayne's current scores: 78, 92, 83, 97?

• A. 19
• B. 85
• C. 83
• D. 87.5

Correct answer: B

Rationale: To find the median of a set of numbers, first arrange the scores in ascending order: 78, 83, 92, 97. Since there is an even number of scores, we find the median by taking the average of the two middle values. In this case, the middle values are 83 and 92. Calculating (83 + 92) / 2 = 85, we determine that the overall median of Dwayne's scores is 85. Choice A (19) is incorrect as it does not correspond to any value in the given set of scores. Choice C (83) is the median of the original set but not the overall median once arranged. Choice D (87.5) is the average of all scores but not the median.

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